The Royal Coding
Addition Of Two Numbers Area And Volume Of Shapes Armstrong Numbers Convert Temperature Even Or Odd Factorial Fibonacci Series Greatest Common Divisor Hello World Largest Among Three Numbers Largest Among Two Least Common Factor Leap Year Multiplication Table Palindrome Number Quotient And Remainder Reverse A Number Sum Of Natural Numbers Swap Two Numbers Vowel Or Consonant Anagrams Of Two Strings

Python/C/C++/JAVA

Basic Practice Programs with Code and Concept

By D.S

Check Leap Year

In this example, we're going to be discussing how to determine whether a given year is a leap year or not using various programming languages. A leap year is a year that is divisible by 4 but not divisible by 100 unless it is also divisible by 400. We'll explore different approaches to implement this logic in C, C++, Python, and Java.

(a.) C Code

#include <stdio.h>

    int main() {
        int year;

        printf("Enter a year: ");
        scanf("%d", &year);

        if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
            printf("%d is a leap year.
", year);
        } else {
            printf("%d is not a leap year.
", year);
        }

        return 0;
    }
Output:-
Enter a year: 2024
2024 is a leap year.

(b.) C++ Code

#include <iostream>

    using namespace std;

    int main() {
        int year;

        cout << "Enter a year: ";
        cin >> year;

        if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
            cout << year << " is a leap year." << endl;
        } else {
            cout << year << " is not a leap year." << endl;
        }

        return 0;
    }
Output:-
Enter a year: 2024
2024 is a leap year.

(c.) Python Code

def is_leap_year(year):
        return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)

    year = int(input("Enter a year: "))
    if is_leap_year(year):
        print(year, "is a leap year.")
    else:
        print(year, "is not a leap year.")
Output:-
Enter a year: 2024
2024 is a leap year.

(d.) Java Code

import java.util.Scanner;

    public class LeapYearChecker {
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            System.out.print("Enter a year: ");
            int year = scanner.nextInt();

            if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) {
                System.out.println(year + " is a leap year.");
            } else {
                System.out.println(year + " is not a leap year.");
            }
        }
    }
Output:-
Enter a year: 2024
2024 is a leap year.